1/6y^2=-y-3/2

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Solution for 1/6y^2=-y-3/2 equation: 


y in (-oo:+oo)

(1/6)*y^2 = -y-(3/2) // + -y-(3/2)

(1/6)*y^2+y+3/2 = 0

1/6*y^2+y+3/2 = 0

DELTA = 1^2-(1/6*3/2*4)

DELTA = 0

y = -1/(1/6*2)

y = -3 or y = -3

y in { -3, -3 }

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